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Date added: 22.4.2015

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In this dissertation we give complete solutions for the intersection problem of latin squares with holes of size 2 and 3. For a pair of 2n x 2n latin squares with holes of size 2 to have k entries in common outside of the holes k {lcub}0, 1, 2,....,MoreIn this dissertation we give complete solutions for the intersection problem of latin squares with holes of size 2 and 3. For a pair of 2n x 2n latin squares with holes of size 2 to have k entries in common outside of the holes k ∈ {lcub}0, 1, 2,...., x = 4n2 - 4n{rcub} / {lcub}x - 1, x - 2, x - 3, x - 5{rcub}. There is, however, an exception for the case of n = 8. For a pair of 3n x 3n latin squares with holes of size 3 to have k entries in common outside of the holes k ∈ {lcub}0, 1, 2,...., x = 9n2 - 9n{rcub} / {lcub}x - 1, x - 2, x - 3, x - 5{rcub}. The intersection problem for latin squares with holes of size 2 and 3. by Charla Baker